LeetCode 49 - Group Anagrams - NeetCode solution

class Solution:
    def group Anagrams(self, strs: List[str]) -> List[List[str]]:
        res = defaultdict(list) # mapping charCount to list of Anagrams
        for s in strs:
            count = [0] * 26 # a ... z

            for c in s:
                count[ord(c) - ord("a")] += 1

            res[tuple(count)].append(s)

        return res.values()