$.ajax({
        type: "POST",
        url: "php/databasee.php",
        data:{"name":56},
        success:function(msg){
          console.log('done');
        },
        error:function(msg){
          console.log('not');
        }
    });

<?php

$servername="localhost";
$username="root";
$password="";
$database="project";
$conn=mysqli_connect($servername, $username, $password, $database);

$tabl=$_POST['name'];
echo $tabl;
?>