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- 1+5+9+...+(4n-3) = n(2n-1)
- P(1): (4n-3) = n(2n-1)
- 4-3 = 1[(2.1)-1]
- 1 = 1 OK
- P(k+1): 1+5+9+...+(4k-3)+(4(k+1)-3) = (k+1)[2(k+1)-1]
- = k(2k-1)+4(k+1)-3
- = 2k²+3k+1 = (k+1)[2(k+1)-1]
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