Pretvaranje broja "n" u brojnu osnovu "b"

#include <iostream>
using namespace std;
main()
{
      int n, b, i=0, a[10];

      cin >> n >> b;

      // (10)21 (2)10101  (8)25

      while (n>0)
      {
            a[i] = n % b;
            n = n / b;
            i = i + 1;
      }

      for (int j = i - 1; j>=0; j--)
      cout << a[j];

      cout << endl;

      system ("PAUSE");
}