Advertisement
Not a member of Pastebin yet?
Sign Up,
it unlocks many cool features!
- /**
- * Definition for a binary tree node.
- * struct TreeNode {
- * int val;
- * TreeNode *left;
- * TreeNode *right;
- * TreeNode() : val(0), left(nullptr), right(nullptr) {}
- * TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
- * TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
- * };
- */
- class Solution {
- public:
- vector<vector<int>> zigzagLevelOrder(TreeNode* root) {
- if(!root) return {};
- queue<TreeNode*> q;
- vector< vector<int> > res;
- q.push(root);
- int level = 0;
- while(!q.empty()){
- int sz = q.size();
- vector<int> curr(sz);
- for(int i=0; i<sz; i++){
- TreeNode *front = q.front();
- q.pop();
- if(level) curr[sz-i-1] = front->val;
- else curr[i] = front->val;
- if(front->left) q.push(front->left);
- if(front->right) q.push(front->right);
- }
- res.push_back(curr);
- level = !level;
- }
- return res;
- }
- };
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement