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Feb 20th, 2019
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  1. $hoje = date('Y-m-d');
  2. $amanha = date('Y-m-d', strtotime($hoje .' +1 day'));
  3.  
  4. if ($hoje != $amanha) {
  5. somar 40 a 19000
  6. }
  7. //hoje imprime 19040, no dia seguinte imprime 19080 e assim por diante atΓ© o fim do ano.
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