chapter 6

#Exercise 6.1 Write a while loop that starts at the last character in the string and works its way backwards to the first character in the string, printing each letter on a separate line, except backwards.

prog_lang='python3'
i=len(prog_lang)
while i>0:
    i-=1
    print(prog_lang[i],'\n')
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#Exercise 6.2 Given that fruit is a string, what does fruit[:] mean?

fruit='string'
print(fruit[:])
#full string
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#Exercise 6.3 Encapsulate this code in a function named count, and generalize it so that it accepts the string and the letter as arguments.

def count(word,l):
    count = 0
    for letter in word:
        if letter == l:
            count = count + 1
    print(count)


userword='banana'
userletter='a'
count(userword,userletter)
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#Exercise 6.4 There is a string method called count that is similar to the function in the previous exercise. Read the documentation of this method at docs.python.org/library/string.html and write an invocation that counts the number of times the letter a occurs in 'banana'.

str_ing='banana'
let_ter='a'
print(str_ing.count(let_ter))
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#Exercise 6.5
str_ing='X-DSPAM-Confidence: 0.8475'
str_ing=str_ing[str_ing.find(':')+1:]
print('Converted string to float :',float(str_ing))
print('Conversion check:',type(str_ing))
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#Excersice 6.6 string methods
word="orange"
print('str.upper=',word.upper())
print('str.lower=',word.lower())
print('str.capitalize=',word.capitalize())
a="chocolate"
print('count of letter o in string a is:',a.count('o'))
b='hello!'
print('str.encode=',b.encode(encoding='utf-8'))
print('str.find=',a.find('o',1,3))
print("1+1 is {}".format(1+1))
print('str.replace =',b.replace('!',' josh',3))
print(a)
print('str.join=',b.join('12345'))
c=" how are you?  \n"
print('str.strip',c.strip())
print('str.swapcase',c.swapcase())
d="...,I am fine so.,"
print('str.lstrip is',d.lstrip('hello.,'))