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- (*
- Problem 6
- The sum of the squares of the first ten natural numbers is,
- 12 + 22 + ... + 102 = 385
- The square of the sum of the first ten natural numbers is,
- (1 + 2 + ... + 10)2 = 552 = 3025
- Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 385 = 2640.
- Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
- (a + b + c + d + e)^2 =a^2 + b^2 + c^2 + d^2 + e^2 + 2a(b + c + d + e) + 2b(c + d + e) + 2c(d + e) + 2de
- *)
- let problem_6 n =
- let rec loop result tempsum n =
- printfn "N = %i" n
- printfn "result = %i" result
- printfn "tempsum = %i" tempsum
- if n <=1 then result
- else
- let newTempsum = tempsum + n
- printfn "newTempsum = %i" newTempsum
- loop (result + (2*(n-1) * newTempsum)) newTempsum (n-1)
- loop 0 0 n
- problem_6 100 |> ignore
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