Session 7 Conditional Operator

CONDITIONAL OPERATOR ( ? : )  or Ternary Operator
>> It Requires 3 Argument            Arg1 ?  Arg2  : Arg3
>> If Arg1 is true, Whole statement is replacement by Arg2.
     Arg1(True) ?  Arg2  : Arg3 >>>>>>>    Arg2
>> If Arg1 is False, Whole statement is replacement by Arg3.
     Arg1(False) ?  Arg2  : Arg3 >>>>>>>    Arg3.

True  = Non-Zero
False = Zero

a= 15?1:2 ;  1
a=10.5?45:78; 45
a= 0?1:2; 2
a=3+0?23:43; 23
a= 10 ?20:30;  20
a= 100?0:200;    0
a=1.5 ? 100:200;  100
a=0?1.2:300;   300
a=3?10:20;    10
a= 3+0?10:20;  10
a=5?10+5:5+15; 15
a=0?5+3:2-5;   -3


Priority
1. !       Unary
2. * / %   Binary
3. + -     Binary
4. > < >= <=  Binary
5. == !=  Binary
6. &&     Binary
7. ||     Binary
8. ?:     Ternary
9. =      Binary


if(a>b)
{
  max=a;
}
else          Conditional      >>> max= b>a(False)?b :a;  max=a;
{              Bitwise Operator>>> max=a+((a-b)>>15)*(a-b);
  max=b;
}




if(a>b && a>c)
{
    max=a;                max= a>b&&a>c ?a : b>c ? b : c;
}                         max= a>b&&a>c?a:b>c?b:c;
else
{
    if(b>c)
   {
     max=b;
   else
   {
     max=c;
   }
}
max= a>b&&a>c? a:b>c?b:c;

a= 8>3?4>7?10:4>7?9>10?20:30:4>7?40:50:6>8?9>1?10:70:80;   50

Step 1: Count No. of ? and : .  If both are Equal then go to next step
Step 2: Goto 1st ( : )  and Match to the nearest left ( ? )  and Repeat
Step 3: All ? and : Matched then there is no error

 a=6>8?2>1?10:3>2?20:30:6>4?4>8?40:6>2?50:60:70;      50


if(x>y)
{
printf("A");
printf("B"); Statement
}
else
{
printf("C");
printf("D");
}
x>y ? printf("A");printf("B");:printf("C");printf("D");;  Invalid
Arg1? Arg2 : Arg3; Syntax
Note : Every Conditional opr can be converted to if else but vice versa not possible.


a=10,b=20;
c = a && b = 30;
printf("%d %d %d",a,b,c); lvalue
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