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Sep 26th, 2017
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Python 0.15 KB | None | 0 0
  1. from lxml import etree
  2.  
  3. a = etree.parse(file)
  4. root = a.getroot()
  5.  
  6. [i.get('href') 'for i in root.xpath('//item[@media-type="application/xhtml+xml"]')]
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