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- #v-MARTYNAS 8
- #n-DOVILTIS 8
- v=8
- n=8
- p=1/2
- #I uzdotis
- #1)
- D<-dbinom(0:n, n, p);D
- sum(D)
- #2)
- A<-pbinom(-1:n, n, p);A
- #3)
- q<--1:8
- x<-0:8
- par(mfrow=c(2,1))
- plot(x,D,type='l',main="Daugiakampis");grid()
- plot(q,A,type='s',main="F(x)");grid()
- #4)
- #Labiausiai tiketinas yra 4, matosi is daugiakampio
- EX<-n*p;EX
- EX1<-sum(x*D);EX1
- #Vidutinis yra 4
- #5)
- #P(x<8)
- p2<-sum(dbinom(0:7,n,p));p2
- #II uzd
- f<-function(x) dnorm(x,v,n/10)
- integrate(f,v-1,v+2)
- a<-v-3*4
- b<-v+3*4
- curve(f,a,b)
- x<-seq(v-1,v+2,0.1)
- y<-dnorm(x,v,n/10)
- x1=c(v-1,x,v+2)
- y1=c(0,y,0)
- polygon(x1,y1,col="blue")
- #III
- #1)
- kiek<-n*50
- kartu<-v*2
- A<-p
- binom <- rbinom(kiek, kartu, A);
- a<-table(binom);a #parodo xi ir ni
- a2<-table(binom)/kiek;a2 #parodo xi/ni
- barplot(a2)
- #2)
- norm<-rnorm(kiek, v, v-2.5)
- funk<-dnorm(kiek,v,v-2.5)
- hist(norm,breaks=15,freq=F)
- curve(dnorm(x,v,v-2.5), add=TRUE, col="darkblue", lwd=2)
- #3)
- q<-0.95
- vid<-v
- nuok<-v-2.5
- #a)
- x<-rnorm(n*50, vid, nuok)
- mean(x)
- I1 <- mean(x)+qt((1-0.95)/2, 650-1)*sd(x)/sqrt(n*50);I1 #kai nuok nezinomas
- I2 <- mean(x)+qt((1+0.95)/2, 650-1)*sd(x)/sqrt(n*50);I2
- var(x)*(n*50-1)/c(qchisq((1+0.95)/2,640-1),qchisq((1-0.95)/2,n*50-1))#kai vid nezinomas
- #b)
- a <- v
- s <- v-2.5
- z <- n*50
- error <- qnorm(0.95)*s/sqrt(z)
- left <- a-error
- right <- a+error
- #IV
- #kiekybinis skaiciai
- #kokybinis nenusakomas skaiciais
- #1) #cia turim kiekybinius tolydziuosius
- data<-read.csv("http://www.principlesofeconometrics.com/poe5/data/csv/france.csv",sep=",", dec=".", head=TRUE)
- data
- #2) #fngap
- #4)
- par(mfrow=c(2,1))
- hist(data$fngap, freq=FALSE, main="Santykiniu dazniu histograma", xlab="fngap")
- boxplot(data$fngap, main="Staciakampiu diagrama", horizontal=TRUE)
- mean(data$fngap)
- var(data$fngap)
- median(data$fngap)
- sd(data$fngap)
- min(data$fngap)
- max(data$fngap)
- Q1<-quantile(data$fngap, probs = seq(0.25, 1))
- Q3<-quantile(data$fngap, probs = seq(0.75, 1))
- Q1
- Q3
- IQR<-Q3-Q1
- IQR
- nuo<-Q1-3*IQR
- iki<-Q3+3*IQR
- nuo
- iki
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