Docmarten

var call1 = $http({url: 'http://www.foobar.com', cache:'false'
	}).then(function(response1){
		//process response1
		return response1
	},function(response){
		//process error
	}) ;

var call2 = $http({url: 'http://www.foobar.com', cache:'false'
	}).then(function(response2){
		//process response2
		return response2
	},function(response){
		//process error
	}) ;

$q.all([call1,call2]).then(function(response){
	for (var x=0,x<response.length;x++) {
   	//process response1 and response2
	}
	return processedResponses ;
}

// Because call1 and call2 are pretty much identical, I should see the same data twice in "processedResponses" - and I am.
// however in the inspector/debug tool I am only seeing ONE call to http://www.foobar.com when I am expecting to see two calls
//
// Thus is call2 not actually happening because call1 is cached and thus response2 is simply pulled from response1???