#64 NumarPerfect

#include <iostream>
using namespace std;
int d, x, s, ct = 0;
int
main ()
{
    cin >> x;
    s = 0;
    for (d = 1; d * d < x; d++)
        if (x % d == 0)
            s = s + d + x / d;
    if (d * d == x)
        s = s + d;
    if (s - x == x)
        cout << x << " este perfect";
    else
        cout << x << " nu este perfect";

    return 0;
}