HW6

/*

Nick Ku                     PIC10A Intro. to Programming

ID: 304491540               Spring 2016

Email: cinestra@ucla.edu    HW #3

Section: 3A

Honesty Pledge:



I, Nichokas Ku, pledge that this is my own independent work, which conforms to

the guidelines of academic honesty as described in the course syllabus.

List of none bugs: None.

*/



#include<iostream>
#include<iomanip>
#include <string>

using namespace std;

bool is_vowel(string letter)
// Taken from lecture slides
{
	if (letter.length() > 1)
		return false;
	if (letter == "a" || letter == "e" || letter == "i" || letter == "o" || letter == "u" || letter == "y")
		return true;
	else if (letter == "A" || letter == "E" || letter == "I" || letter == "O" || letter == "U" || letter == "Y")
		return true;
	else
		return false;
}

bool is_punctuation(string letter)
// Exactly the same as is_vowel but with different characters and less cases
{
	if (letter.length() > 1)
		return false;
	if (letter == "." || letter == "!" || letter == ";" || letter == ":")
		return true;
	else
		return false;
}

int number_of_sentences(string phrase)
// Returns the number of sentences from the whole phrase by counting the number of punctuations
{
	int count = 0;

	for (int i = 0; i<phrase.length(); i++)
	{
		if (is_punctuation(phrase.substr(i, 1)))
			count++;
	}

	return count;
}

int number_of_words(string phrase)
// Returns the number of words from the whole phrase by counting the number of spaces and adding one
{
	int spaces = 0;
	for (int i=0; i < phrase.length(); i++)
	{

		if ((phrase.substr(i, 1) == " ") && (phrase.substr(i+1, 1) != " "))
		{
			// Increments the number of spaces whenever a space is found
			// Will not increment if the following space is also blank
			spaces++;
		}
	}

		return spaces+1;
}

string next_word(string phrase)
// Returns the next word in the string phrase by taking the substring from 0 to the next open space or taking the substring from 0 to the end length
// Runs into a problem when there are two spaces next to each other since it will count one space character by itself as a letter
// Resolve this problem later by setting the number of syllables for that one space character equal to zero
{
	string phrase_word;
	int i = 0;



	while (((phrase.substr(i, 1) != " ") || !(is_punctuation(phrase.substr(i,1)))) && (i<phrase.length()))
	{
		i++;
	}
	phrase_word = phrase.substr(0, i);
	// Using i-1 instead of simply i because i locates the space whereas i-1 locates the letter before the space

	return phrase_word;
}


int number_of_syllables(string word)

{
	int n_syllables = 0;
	string prev_char;

	for (int i = 0; i < word.length(); ++i)
	{
		string cur_char = word.substr(i, 1);

		if (i == 0) prev_char = "b";
		else prev_char = word.substr(i - 1, 1);

		if ((cur_char == "e") && (i == word.length()))
			n_syllables = n_syllables + 0;
		// Do nothing
		else if ((is_vowel(cur_char)) && !(is_vowel(prev_char)))
			n_syllables++;
	}

	return n_syllables;
}

int readability_index(int nsyllables, int nwords, int nsentences)
{
	double x = nsyllables;
	double y = nwords;
	double z = nsentences;

	double index = 206.835 - 84.6*(x / y) - 1.015 * (y / z);
	return index;
}

int main()
{
	string phrase;
	string first_word;
	string phrase_copy;
	cout << "Please enter a phrase: " << "\n";
	getline(cin, phrase);

	phrase_copy = phrase;

	long count = 0;

	while (phrase_copy.length() > 0)
	{
		first_word = next_word(phrase_copy);
		long a = number_of_syllables(first_word);
		long b = first_word.length();

		phrase_copy = phrase_copy.substr(b, phrase_copy.length());
		count = count + a;
	}

	int nSyllables = count;
	// Recasts count into an integer

	int nWords = number_of_words(phrase);
	int nSentences = number_of_sentences(phrase);
	int index = readability_index(nSyllables, nWords, nSentences);

	cout << "number of syllables is: " << nSyllables << "\n";
	cout << "number of words is: " << nWords << "\n";
	cout << "number of sentences is: " << nSentences << "\n";
	cout << "readibility index is : " << index << "\n";
	system("pause");

	return 0;

}