Advertisement
Not a member of Pastebin yet?
Sign Up,
it unlocks many cool features!
- y₁= [(ST/10) * (1 + t/(d/3))]ai
- y₂= {[(ST/20) * (1 + t/(d/3))] + [1 + L(ST/50]}ai
- ST = Stat Total
- t = turns passed in battle
- d = damage taken by player
- L = level of enemy
- a = If it's a player, 1.5x, if it's a computer-controlled enemy, 1
- i = Multipliers from items
- ex: A Liontamer defeats a player-controlled Peasant with a stat total of 200. The Peasant was defeated in 9 turns, but inflicted 23 damage before being defeated. The Peasant's level is 1, and the Liontamer is holding no items to boost exp
- y₁= [(200/10) * (1 + 9/(23/3))]1.5
- (20 * 2.17)1.5
- (43)1.5
- y₁= 65 experience
- y₂= {[(200/20) * (1 + 9/(23/3))] + [1 + 1(200/50]}1.5
- [(10 * 2.17) + (5)]1.5
- (22 + 5)1.5
- (27)1.5
- y₂= 41 experience
- ex2: A Nurse defeats a player-controlled Peasant with a stat total of 500. The Peasant was defeated in 14 turns, but inflicted 20 damage before being defeated. The Peasant's level is 34, and the Nurse has a ring that grants them a 10% exp boost.
- y₁= [(500/10) * (1 + 14/(20/3))](1.5 * 1.1)
- (50 * 2.1)1.65
- 173
- y₁= 173 experience
- y₂= {[(500/20) * (1 + 14/(20/3))] + [1 + 34(500/50]}1.65
- [(25 * 2.1) + (341)]1.65
- [(52) + (341)]1.65
- (393)1.65
- 649
- y₂= 649 experience
- Conclusion: Equation 1 will grant more experience initially, but Equation 2 will grant more experience when enemies start getting into higher levels.
- *Edit: Equation changed to {[(ST/18.5) * (1 + t/(d/1.65)] + [1 + L(ST/50]}ai
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement