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Oct 16th, 2017
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  1. Solve[((k^(1 - β) (n + δk))/sk)^(1/γ) == ((k^β sh)/(n + δh))^(1/(1 - γ)), k]
  2.  
  3. {{k ->
  4. E^((-γ Log[sh] + (-1 + γ) Log[sk] + γ Log[n + δh] - (-1 + γ) Log[n + δk])/
  5. (-1 + β + γ))}}
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