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a guest Apr 19th, 2019 69 Never
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  1. import java.util.*;
  2. import java.security.*;
  3. public class Solution {
  4.  public static void main(String[] args) {
  5.  
  6.   DoNotTerminate.forbidExit();
  7.  
  8.   try {
  9.    Scanner in = new Scanner(System.in);
  10.    int n = in .nextInt();
  11.    in.close();
  12.    //String s=???; Complete this line below
  13.  
  14.     String s = Integer.toString(n);
  15.  
  16.  
  17.    
  18.    if (n == Integer.parseInt(s)) {
  19.     System.out.println("Good job");
  20.    } else {
  21.     System.out.println("Wrong answer.");
  22.    }
  23.   } catch (DoNotTerminate.ExitTrappedException e) {
  24.    System.out.println("Unsuccessful Termination!!");
  25.   }
  26.  }
  27. }
  28.  
  29. //The following class will prevent you from terminating the code using exit(0)!
  30. class DoNotTerminate {
  31.  
  32.  public static class ExitTrappedException extends SecurityException {
  33.  
  34.   private static final long serialVersionUID = 1;
  35.  }
  36.  
  37.  public static void forbidExit() {
  38.   final SecurityManager securityManager = new SecurityManager() {
  39.    @Override
  40.    public void checkPermission(Permission permission) {
  41.     if (permission.getName().contains("exitVM")) {
  42.      throw new ExitTrappedException();
  43.     }
  44.    }
  45.   };
  46.   System.setSecurityManager(securityManager);
  47.  }
  48. }
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