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Jul 15th, 2018
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  1. 2^23 > s > 0
  2. x = int(s/2^16) + int(((s * 1103515245) + 24691) % 2^32)/2^16) * 2^16
  3. x % 100 = a % 25
  4. x % 2^8 > b
  5. x % 2 = c
  6.  
  7. Given a, b, and c, solve for any x.
  8.  
  9. Multiple solutions are available.
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