Examen de bacalaureat 2020 - Variante propuse - Testul 2 (Matematica Informatica)

I.1.d
  2.c
  3.b
  4.b
  5.a

II.
  1.a)20950
    b)20202 40404 60606
    c)
#include<iostream>
using namespace std;
int main()
{int n,m,c;
cin>>n;
m=0;
do{c=n%10;
   n=n/10;
   if(c==0)
    c=2;
   else
    if(c%2==0)
      c=0;
   m=m*10+c;
}while(n)
cout<<m;}
    d)
citeşte n (număr natural)
m=0
c=n%10; n=[n/10]
┌dacă c=0 atunci c=2
│altfel
│┌dacă c%2=0 atunci
││c=0
│└■
└■
 m=m*10+c
┌cat timp n=0 executa
│ c=n%10; n=[n/10]
│┌dacă c=0 atunci c=2
││altfel
││┌dacă c%2=0 atunci
│││c=0
││└■
│└■
│ m=m*10+c
└■
scrie m

   2.
struct {int cod;
        int nrExemplare;
        int varsta[10];
        }s[20];
   3.
for(i=0;i<5;i++)
for(j=0;j<7;j++)
if(i==0 || j==0)
a[i][j]=1;
else
a[i][j]=(a[i-1][j]+a[i][j-1])%10;

III.
   1.
void(int n)
{int i;
for(i=1;i*i<=n;i++)
if(n%i==0 && i*i<n)
cout<<"("<<n/i<<" "<<i<<")"<<" ";
}
   2.

   3.
#include<iostream>
#include<fstream>
using namespace std;
ifstream fin("bac.txt");
int main()
{int x,a=0,aa=0,c=0;
while(fin>>x)
{if(x>c && x%100==20)
{aa=a;
a=c;
c=x;}
else
if(x>a && x%100==20)
{aa=a;
a=x;}
else
if(x>aa && x%100==20)
aa=x;
}
cout<<aa<<" "<<a<<" "<<c;
}