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- Pocetok = input()
- Kraj = input()
- import sys
- import bisect
- infinity = float('inf') # sistemski definirana vrednost za beskonecnost
- # ______________________________________________________________________________________________
- # Definiranje na pomosni strukturi za cuvanje na listata na generirani, no neprovereni jazli
- class Queue:
- """Queue is an abstract class/interface. There are three types:
- Stack(): A Last In First Out Queue.
- FIFOQueue(): A First In First Out Queue.
- PriorityQueue(order, f): Queue in sorted order (default min-first).
- Each type supports the following methods and functions:
- q.append(item) -- add an item to the queue
- q.extend(items) -- equivalent to: for item in items: q.append(item)
- q.pop() -- return the top item from the queue
- len(q) -- number of items in q (also q.__len())
- item in q -- does q contain item?
- Note that isinstance(Stack(), Queue) is false, because we implement stacks
- as lists. If Python ever gets interfaces, Queue will be an interface."""
- def __init__(self):
- raise NotImplementedError
- def extend(self, items):
- for item in items:
- self.append(item)
- def Stack():
- """A Last-In-First-Out Queue."""
- return []
- class FIFOQueue(Queue):
- """A First-In-First-Out Queue."""
- def __init__(self):
- self.A = []
- self.start = 0
- def append(self, item):
- self.A.append(item)
- def __len__(self):
- return len(self.A) - self.start
- def extend(self, items):
- self.A.extend(items)
- def pop(self):
- e = self.A[self.start]
- self.start += 1
- if self.start > 5 and self.start > len(self.A) / 2:
- self.A = self.A[self.start:]
- self.start = 0
- return e
- def __contains__(self, item):
- return item in self.A[self.start:]
- class PriorityQueue(Queue):
- """A queue in which the minimum (or maximum) element (as determined by f and
- order) is returned first. If order is min, the item with minimum f(x) is
- returned first; if order is max, then it is the item with maximum f(x).
- Also supports dict-like lookup. This structure will be most useful in informed searches"""
- def __init__(self, order=min, f=lambda x: x):
- self.A = []
- self.order = order
- self.f = f
- def append(self, item):
- bisect.insort(self.A, (self.f(item), item))
- def __len__(self):
- return len(self.A)
- def pop(self):
- if self.order == min:
- return self.A.pop(0)[1]
- else:
- return self.A.pop()[1]
- def __contains__(self, item):
- return any(item == pair[1] for pair in self.A)
- def __getitem__(self, key):
- for _, item in self.A:
- if item == key:
- return item
- def __delitem__(self, key):
- for i, (value, item) in enumerate(self.A):
- if item == key:
- self.A.pop(i)
- # ______________________________________________________________________________________________
- # Definiranje na klasa za strukturata na problemot koj ke go resavame so prebaruvanje
- # Klasata Problem e apstraktna klasa od koja pravime nasleduvanje za definiranje na osnovnite karakteristiki
- # na sekoj eden problem sto sakame da go resime
- class Problem:
- """The abstract class for a formal problem. You should subclass this and
- implement the method successor, and possibly __init__, goal_test, and
- path_cost. Then you will create instances of your subclass and solve them
- with the various search functions."""
- def __init__(self, initial, goal=None):
- """The constructor specifies the initial state, and possibly a goal
- state, if there is a unique goal. Your subclass's constructor can add
- other arguments."""
- self.initial = initial
- self.goal = goal
- def successor(self, state):
- """Given a state, return a dictionary of {action : state} pairs reachable
- from this state. If there are many successors, consider an iterator
- that yields the successors one at a time, rather than building them
- all at once. Iterators will work fine within the framework. Yielding is not supported in Python 2.7"""
- raise NotImplementedError
- def actions(self, state):
- """Given a state, return a list of all actions possible from that state"""
- raise NotImplementedError
- def result(self, state, action):
- """Given a state and action, return the resulting state"""
- raise NotImplementedError
- def goal_test(self, state):
- """Return True if the state is a goal. The default method compares the
- state to self.goal, as specified in the constructor. Implement this
- method if checking against a single self.goal is not enough."""
- return state == self.goal
- def path_cost(self, c, state1, action, state2):
- """Return the cost of a solution path that arrives at state2 from
- state1 via action, assuming cost c to get up to state1. If the problem
- is such that the path doesn't matter, this function will only look at
- state2. If the path does matter, it will consider c and maybe state1
- and action. The default method costs 1 for every step in the path."""
- return c + 1
- def value(self):
- """For optimization problems, each state has a value. Hill-climbing
- and related algorithms try to maximize this value."""
- raise NotImplementedError
- # ______________________________________________________________________________
- # Definiranje na klasa za strukturata na jazel od prebaruvanje
- # Klasata Node ne se nasleduva
- class Node:
- """A node in a search tree. Contains a pointer to the parent (the node
- that this is a successor of) and to the actual state for this node. Note
- that if a state is arrived at by two paths, then there are two nodes with
- the same state. Also includes the action that got us to this state, and
- the total path_cost (also known as g) to reach the node. Other functions
- may add an f and h value; see best_first_graph_search and astar_search for
- an explanation of how the f and h values are handled. You will not need to
- subclass this class."""
- def __init__(self, state, parent=None, action=None, path_cost=0):
- "Create a search tree Node, derived from a parent by an action."
- self.state = state
- self.parent = parent
- self.action = action
- self.path_cost = path_cost
- self.depth = 0
- if parent:
- self.depth = parent.depth + 1
- def __repr__(self):
- return "<Node %s>" % (self.state,)
- def __lt__(self, node):
- return self.state < node.state
- def expand(self, problem):
- "List the nodes reachable in one step from this node."
- return [self.child_node(problem, action)
- for action in problem.actions(self.state)]
- def child_node(self, problem, action):
- "Return a child node from this node"
- next = problem.result(self.state, action)
- return Node(next, self, action,
- problem.path_cost(self.path_cost, self.state,
- action, next))
- def solution(self):
- "Return the sequence of actions to go from the root to this node."
- return [node.action for node in self.path()[1:]]
- def solve(self):
- "Return the sequence of states to go from the root to this node."
- return [node.state for node in self.path()[0:]]
- def path(self):
- "Return a list of nodes forming the path from the root to this node."
- x, result = self, []
- while x:
- result.append(x)
- x = x.parent
- return list(reversed(result))
- # We want for a queue of nodes in breadth_first_search or
- # astar_search to have no duplicated states, so we treat nodes
- # with the same state as equal. [Problem: this may not be what you
- # want in other contexts.]
- def __eq__(self, other):
- return isinstance(other, Node) and self.state == other.state
- def __hash__(self):
- return hash(self.state)
- # ________________________________________________________________________________________________________
- #Neinformirano prebaruvanje vo ramki na drvo
- #Vo ramki na drvoto ne razresuvame jamki
- def tree_search(problem, fringe):
- """Search through the successors of a problem to find a goal.
- The argument fringe should be an empty queue."""
- fringe.append(Node(problem.initial))
- while fringe:
- node = fringe.pop()
- print node.state
- if problem.goal_test(node.state):
- return node
- fringe.extend(node.expand(problem))
- return None
- def breadth_first_tree_search(problem):
- "Search the shallowest nodes in the search tree first."
- return tree_search(problem, FIFOQueue())
- def depth_first_tree_search(problem):
- "Search the deepest nodes in the search tree first."
- return tree_search(problem, Stack())
- # ________________________________________________________________________________________________________
- #Neinformirano prebaruvanje vo ramki na graf
- #Osnovnata razlika e vo toa sto ovde ne dozvoluvame jamki t.e. povtoruvanje na sostojbi
- def graph_search(problem, fringe):
- """Search through the successors of a problem to find a goal.
- The argument fringe should be an empty queue.
- If two paths reach a state, only use the best one."""
- closed = {}
- fringe.append(Node(problem.initial))
- while fringe:
- node = fringe.pop()
- if problem.goal_test(node.state):
- return node
- if node.state not in closed:
- closed[node.state] = True
- fringe.extend(node.expand(problem))
- return None
- def breadth_first_graph_search(problem):
- "Search the shallowest nodes in the search tree first."
- return graph_search(problem, FIFOQueue())
- def depth_first_graph_search(problem):
- "Search the deepest nodes in the search tree first."
- return graph_search(problem, Stack())
- def uniform_cost_search(problem):
- "Search the nodes in the search tree with lowest cost first."
- return graph_search(problem, PriorityQueue(lambda a, b: a.path_cost < b.path_cost))
- def depth_limited_search(problem, limit=50):
- "depth first search with limited depth"
- def recursive_dls(node, problem, limit):
- "helper function for depth limited"
- cutoff_occurred = False
- if problem.goal_test(node.state):
- return node
- elif node.depth == limit:
- return 'cutoff'
- else:
- for successor in node.expand(problem):
- result = recursive_dls(successor, problem, limit)
- if result == 'cutoff':
- cutoff_occurred = True
- elif result != None:
- return result
- if cutoff_occurred:
- return 'cutoff'
- else:
- return None
- # Body of depth_limited_search:
- return recursive_dls(Node(problem.initial), problem, limit)
- def iterative_deepening_search(problem):
- for depth in xrange(sys.maxint):
- result = depth_limited_search(problem, depth)
- if result is not 'cutoff':
- return result
- # ________________________________________________________________________________________________________
- #Pomosna funkcija za informirani prebaruvanja
- #So pomos na ovaa funkcija gi keshirame rezultatite od funkcijata na evaluacija
- def memoize(fn, slot=None):
- """Memoize fn: make it remember the computed value for any argument list.
- If slot is specified, store result in that slot of first argument.
- If slot is false, store results in a dictionary."""
- if slot:
- def memoized_fn(obj, *args):
- if hasattr(obj, slot):
- return getattr(obj, slot)
- else:
- val = fn(obj, *args)
- setattr(obj, slot, val)
- return val
- else:
- def memoized_fn(*args):
- if not memoized_fn.cache.has_key(args):
- memoized_fn.cache[args] = fn(*args)
- return memoized_fn.cache[args]
- memoized_fn.cache = {}
- return memoized_fn
- # ________________________________________________________________________________________________________
- #Informirano prebaruvanje vo ramki na graf
- def best_first_graph_search(problem, f):
- """Search the nodes with the lowest f scores first.
- You specify the function f(node) that you want to minimize; for example,
- if f is a heuristic estimate to the goal, then we have greedy best
- first search; if f is node.depth then we have breadth-first search.
- There is a subtlety: the line "f = memoize(f, 'f')" means that the f
- values will be cached on the nodes as they are computed. So after doing
- a best first search you can examine the f values of the path returned."""
- f = memoize(f, 'f')
- node = Node(problem.initial)
- if problem.goal_test(node.state):
- return node
- frontier = PriorityQueue(min, f)
- frontier.append(node)
- explored = set()
- while frontier:
- node = frontier.pop()
- if problem.goal_test(node.state):
- return node
- explored.add(node.state)
- for child in node.expand(problem):
- if child.state not in explored and child not in frontier:
- frontier.append(child)
- elif child in frontier:
- incumbent = frontier[child]
- if f(child) < f(incumbent):
- del frontier[incumbent]
- frontier.append(child)
- return None
- def greedy_best_first_graph_search(problem, h=None):
- "Greedy best-first search is accomplished by specifying f(n) = h(n)"
- h = memoize(h or problem.h, 'h')
- return best_first_graph_search(problem, h)
- def astar_search(problem, h=None):
- "A* search is best-first graph search with f(n) = g(n)+h(n)."
- h = memoize(h or problem.h, 'h')
- return best_first_graph_search(problem, lambda n: n.path_cost + h(n))
- # ________________________________________________________________________________________________________
- #Dopolnitelni prebaruvanja
- #Recursive_best_first_search e implementiran
- #Kako zadaca za studentite da gi implementiraat SMA* i IDA*
- def recursive_best_first_search(problem, h=None):
- h = memoize(h or problem.h, 'h')
- def RBFS(problem, node, flimit):
- if problem.goal_test(node.state):
- return node, 0 # (The second value is immaterial)
- successors = node.expand(problem)
- if len(successors) == 0:
- return None, infinity
- for s in successors:
- s.f = max(s.path_cost + h(s), node.f)
- while True:
- # Order by lowest f value
- successors.sort(key=lambda x: x.f)
- best = successors[0]
- if best.f > flimit:
- return None, best.f
- if len(successors) > 1:
- alternative = successors[1].f
- else:
- alternative = infinity
- result, best.f = RBFS(problem, best, min(flimit, alternative))
- if result is not None:
- return result, best.f
- node = Node(problem.initial)
- node.f = h(node)
- result, bestf = RBFS(problem, node, infinity)
- return result
- # _________________________________________________________________________________________________________
- #PRIMER 1 : PROBLEM SO DVA SADA SO VODA
- #OPIS: Dadeni se dva sada J0 i J1 so kapaciteti C0 i C1
- #Na pocetok dvata sada se polni. Inicijalnata sostojba moze da se prosledi na pocetok
- #Problemot e kako da se stigne do sostojba vo koja J0 ke ima G0 litri, a J1 ke ima G1 litri
- #AKCII: 1. Da se isprazni bilo koj od sadovite
- #2. Da se prefrli tecnosta od eden sad vo drug so toa sto ne moze da se nadmine kapacitetot na sadovite
- # Moze da ima i opcionalen tret vid na akcii 3. Napolni bilo koj od sadovite (studentite da ja implementiraat ovaa varijanta)
- # ________________________________________________________________________________________________________
- class WJ(Problem):
- """STATE: Torka od oblik (3,2) if jug J0 has 3 liters and J1 2 liters
- Opcionalno moze za nekoj od sadovite da se sretne i vrednost '*' sto znaci deka e nebitno kolku ima vo toj sad
- GOAL: Predefinirana sostojba do kade sakame da stigneme. Ako ne interesira samo eden sad za drugiot mozeme da stavime '*'
- PROBLEM: Se specificiraat kapacitetite na sadovite, pocetna sostojba i cel """
- def __init__(self, capacities=(5, 2), initial=(5, 0), goal=(0, 1)):
- self.capacities = capacities
- self.initial = initial
- self.goal = goal
- def goal_test(self, state):
- """ Vraka true ako sostojbata e celna """
- g = self.goal
- return (state[0] == g[0] or g[0] == '*') and \
- (state[1] == g[1] or g[1] == '*')
- def successor(self, J):
- """Vraka recnik od sledbenici na sostojbata"""
- successors = dict()
- J0, J1 = J
- (C0, C1) = self.capacities
- if J0 > 0:
- Jnew = 0, J1
- successors['dump jug 0'] = Jnew
- if J1 > 0:
- Jnew = J0, 0
- successors['dump jug 1'] = Jnew
- if J1 < C1 and J0 > 0:
- delta = min(J0, C1 - J1)
- Jnew = J0 - delta, J1 + delta
- successors['pour jug 0 into jug 1'] = Jnew
- if J0 < C0 and J1 > 0:
- delta = min(J1, C0 - J0)
- Jnew = J0 + delta, J1 - delta
- successors['pour jug 1 into jug 0'] = Jnew
- return successors
- def actions(self, state):
- return self.successor(state).keys()
- def result(self, state, action):
- possible = self.successor(state)
- return possible[action]
- # So vaka definiraniot problem mozeme da gi koristime site neinformirani prebaruvanja
- # Vo prodolzenie se dadeni mozni povici (vnimavajte za da moze da napravite povik mora da definirate problem)
- #
- # WJInstance = WJ((5, 2), (5, 2), ('*', 1))
- # print WJInstance
- #
- # answer1 = breadth_first_tree_search(WJInstance)
- # print answer1.solve()
- #
- # answer2 = depth_first_tree_search(WJInstance) #vnimavajte na ovoj povik, moze da vleze vo beskonecna jamka
- # print answer2.solve()
- #
- # answer3 = breadth_first_graph_search(WJInstance)
- # print answer3.solve()
- #
- # answer4 = depth_first_graph_search(WJInstance)
- # print answer4.solve()
- #
- # answer5 = depth_limited_search(WJInstance)
- # print answer5.solve()
- #
- # answer6 = iterative_deepening_search(WJInstance)
- # print answer6.solve()
- # _________________________________________________________________________________________________________
- #PRIMER 2 : PROBLEM NA SLOZUVALKA
- #OPIS: Dadena e slozuvalka 3x3 na koja ima polinja so brojki od 1 do 8 i edno prazno pole
- # Praznoto pole e obelezano so *. Eden primer na slozuvalka e daden vo prodolzenie:
- # -------------
- # | * | 3 | 2 |
- # |---|---|---|
- # | 4 | 1 | 5 |
- # |---|---|---|
- # | 6 | 7 | 8 |
- # -------------
- #Problemot e kako da se stigne do nekoja pocetna raspredelba na polinjata do nekoja posakuvana, na primer do:
- # -------------
- # | * | 1 | 2 |
- # |---|---|---|
- # | 3 | 4 | 5 |
- # |---|---|---|
- # | 6 | 7 | 8 |
- # -------------
- #AKCII: Akciite ke gi gledame kako dvizenje na praznoto pole, pa mozni akcii se : gore, dole, levo i desno.
- #Pri definiranjeto na akciite mora da se vnimava dali akciite voopsto mozat da se prevzemat vo dadenata slozuvalka
- #STATE: Sostojbata ke ja definirame kako string koj ke ima 9 karakteri (po eden za sekoe brojce plus za *)
- #pri sto stringot ke se popolnuva so izminuvanje na slozuvalkata od prviot kon tretiot red, od levo kon desno.
- # Na primer sostojbata za pocetnata slozuvalka e: '*32415678'
- # Sostojbata za finalnata slozuvalka e: '*12345678'
- # ________________________________________________________________________________________________________
- #
- default_goal = '*12345678' #predefinirana cel
- #Ke definirame 3 klasi za problemot
- #Prvata klasa nema implementirano nikakva hevristika
- class P8(Problem):
- name = 'No Heuristic'
- def __init__(self, goal=default_goal, initial=None, N=20):
- self.goal = goal
- self.initial = initial
- def successor(self, state):
- return successor8(state)
- def actions(self, state):
- return self.successor(state).keys()
- def h(self, node):
- """Heuristic for 8 puzzle: returns 0"""
- return 0
- def result(self, state, action):
- possible = self.successor(state)
- return possible[action]
- #Slednite klasi ke nasleduvaat od prethodnata bez hevristika so toa sto ovde ke ja definirame i hevristikata
- class P8_h1(P8):
- """ Slozuvalka so hevristika
- HEVRISTIKA: Brojot na polinja koi ne se na vistinskoto mesto"""
- name = 'Out of Place Heuristic'
- def h(self, node):
- """Funkcija koja ja presmetuva hevristikata,
- t.e. razlikata pomegu nekoj tekoven jazel od prebaruvanjeto i celniot jazel"""
- matches = 0
- for (t1, t2) in zip(node.state, self.goal):
- #zip funkcijata od dve listi na vlez pravi edna lista od parovi (torki)
- #primer: zip(['a','b','c'],[1,2,3]) == [('a',1),('b',2),('c',3)]
- # zip('abc','123') == [('a','1'),('b','2'),('c','3')]
- if t1 != t2:
- matches = + 1
- return matches
- class P8_h2(P8):
- """ Slozuvalka so hevristika
- HEVRISTIKA: Menheten rastojanie do celna sostojba"""
- name = 'Manhattan Distance Heuristic (MHD)'
- def h(self, node):
- """Funkcija koja ja presmetuva hevristikata,
- t.e. Menheten rastojanieto pomegu nekoj tekoven jazel od prebaruvanjeto i celniot jazel, pri sto
- Menheten rastojanieto megu jazlite e zbir od Menheten rastojanijata pomegu istite broevi vo dvata jazli"""
- sum = 0
- for c in '12345678':
- sum = + mhd(node.state.index(c), self.goal.index(c)) #pomosna funkcija definirana vo prodolzenie
- return sum
- # Za da mozeme da go definirame rastojanieto treba da definirame koordinaten sistem
- # Pozetokot na koordinatniot sistem e postaven vo gorniot lev agol na slozuvalkata
- # Definirame recnik za koordinatite na sekoe pole od slozuvalkata
- coordinates = {0: (0, 0), 1: (1, 0), 2: (2, 0),
- 3: (0, 1), 4: (1, 1), 5: (2, 1),
- 6: (0, 2), 7: (1, 2), 8: (2, 2)}
- #Funkcija koja presmetuva Menheten rastojanie za slozuvalkata
- #Na vlez dobiva dva celi broja koi odgovaraat na dve polinja na koi se naogaat broevite za koi treba da presmetame rastojanie
- def mhd(n, m):
- x1, y1 = coordinates[n]
- x2, y2 = coordinates[m]
- return abs(x1 - x2) + abs(y1 - y2)
- def successor8(S):
- """Pomosna funkcija koja generira recnik za sledbenicite na daden jazel"""
- blank = S.index('*') #kade se naoga praznoto pole
- succs = {}
- # GORE: Ako praznoto pole ne e vo prviot red, togas vo sostojbata napravi swap
- # na praznoto pole so brojceto koe se naoga na poleto nad nego
- if blank > 2:
- swap = blank - 3
- succs['GORE'] = S[0:swap] + '*' + S[swap + 1:blank] + S[swap] + S[blank + 1:]
- # DOLE: Ako praznoto pole ne e vo posledniot red, togas vo sostojbata napravi swap
- # na praznoto pole so brojceto koe se naoga na poleto pod nego
- if blank < 6:
- swap = blank + 3
- succs['DOLE'] = S[0:blank] + S[swap] + S[blank + 1:swap] + '*' + S[swap + 1:]
- # LEVO: Ako praznoto pole ne e vo prvata kolona, togas vo sostojbata napravi swap
- # na praznoto pole so brojceto koe se naoga na poleto levo od nego
- if blank % 3 > 0:
- swap = blank - 1
- succs['LEVO'] = S[0:swap] + '*' + S[swap] + S[blank + 1:]
- # DESNO: Ako praznoto pole ne e vo poslednata kolona, togas vo sostojbata napravi swap
- # na praznoto pole so brojceto koe se naoga na poleto desno od nego
- if blank % 3 < 2:
- swap = blank + 1
- succs['DESNO'] = S[0:blank] + S[swap] + '*' + S[swap + 1:]
- return succs
- # So vaka definiraniot problem mozeme da gi koristime site informirani, no i neinformirani prebaruvanja
- # Vo prodolzenie se dadeni mozni povici (vnimavajte za da moze da napravite povik mora da definirate problem)
- #
- # s='*32415678'
- # p1=P8(initial=s)
- # p2=P8_h1(initial=s)
- # p3=P8_h2(initial=s)
- #
- # answer1 = greedy_best_first_graph_search(p1)
- # print answer1.solve()
- #
- # answer2 = greedy_best_first_graph_search(p2)
- # print answer2.solve()
- #
- # answer3 = greedy_best_first_graph_search(p3)
- # print answer3.solve()
- #
- # answer4 = astar_search(p1)
- # print answer4.solve()
- #
- # answer5 = astar_search(p2)
- # print answer5.solve()
- #
- # answer6 = astar_search(p3)
- # print answer6.solve()
- #
- # answer7 = recursive_best_first_search(p1)
- # print answer7.solve()
- #
- # answer8 = recursive_best_first_search(p2)
- # print answer8.solve()
- #
- # answer9 = recursive_best_first_search(p3)
- # print answer9.solve()
- # Graphs and Graph Problems
- class Graph:
- """A graph connects nodes (verticies) by edges (links). Each edge can also
- have a length associated with it. The constructor call is something like:
- g = Graph({'A': {'B': 1, 'C': 2})
- this makes a graph with 3 nodes, A, B, and C, with an edge of length 1 from
- A to B, and an edge of length 2 from A to C. You can also do:
- g = Graph({'A': {'B': 1, 'C': 2}, directed=False)
- This makes an undirected graph, so inverse links are also added. The graph
- stays undirected; if you add more links with g.connect('B', 'C', 3), then
- inverse link is also added. You can use g.nodes() to get a list of nodes,
- g.get('A') to get a dict of links out of A, and g.get('A', 'B') to get the
- length of the link from A to B. 'Lengths' can actually be any object at
- all, and nodes can be any hashable object."""
- def __init__(self, dict=None, directed=True):
- self.dict = dict or {}
- self.directed = directed
- if not directed:
- self.make_undirected()
- def make_undirected(self):
- """Make a digraph into an undirected graph by adding symmetric edges."""
- for a in list(self.dict.keys()):
- for (b, dist) in self.dict[a].items():
- self.connect1(b, a, dist)
- def connect(self, A, B, distance=1):
- """Add a link from A and B of given distance, and also add the inverse
- link if the graph is undirected."""
- self.connect1(A, B, distance)
- if not self.directed:
- self.connect1(B, A, distance)
- def connect1(self, A, B, distance):
- """Add a link from A to B of given distance, in one direction only."""
- self.dict.setdefault(A, {})[B] = distance
- def get(self, a, b=None):
- """Return a link distance or a dict of {node: distance} entries.
- .get(a,b) returns the distance or None;
- .get(a) returns a dict of {node: distance} entries, possibly {}."""
- links = self.dict.setdefault(a, {})
- if b is None:
- return links
- else:
- return links.get(b)
- def nodes(self):
- """Return a list of nodes in the graph."""
- return list(self.dict.keys())
- def UndirectedGraph(dict=None):
- """Build a Graph where every edge (including future ones) goes both ways."""
- return Graph(dict=dict, directed=False)
- def RandomGraph(nodes=list(range(10)), min_links=2, width=400, height=300,
- curvature=lambda: random.uniform(1.1, 1.5)):
- """Construct a random graph, with the specified nodes, and random links.
- The nodes are laid out randomly on a (width x height) rectangle.
- Then each node is connected to the min_links nearest neighbors.
- Because inverse links are added, some nodes will have more connections.
- The distance between nodes is the hypotenuse times curvature(),
- where curvature() defaults to a random number between 1.1 and 1.5."""
- g = UndirectedGraph()
- g.locations = {}
- # Build the cities
- for node in nodes:
- g.locations[node] = (random.randrange(width), random.randrange(height))
- # Build roads from each city to at least min_links nearest neighbors.
- for i in range(min_links):
- for node in nodes:
- if len(g.get(node)) < min_links:
- here = g.locations[node]
- def distance_to_node(n):
- if n is node or g.get(node, n):
- return infinity
- return distance(g.locations[n], here)
- neighbor = argmin(nodes, key=distance_to_node)
- d = distance(g.locations[neighbor], here) * curvature()
- g.connect(node, neighbor, int(d))
- return g
- class GraphProblem(Problem):
- """The problem of searching a graph from one node to another."""
- def __init__(self, initial, goal, graph):
- Problem.__init__(self, initial, goal)
- self.graph = graph
- def actions(self, A):
- """The actions at a graph node are just its neighbors."""
- return list(self.graph.get(A).keys())
- def result(self, state, action):
- """The result of going to a neighbor is just that neighbor."""
- return action
- def path_cost(self, cost_so_far, A, action, B):
- return cost_so_far + (self.graph.get(A, B) or infinity)
- # hevristika - broj na hopovi * cenata na rebroto so min vrednost
- def h(self, node):
- min_weight = min_cena(self.graph)
- node=breadth_first_graph_search(GraphProblem(node.state, self.goal, self.graph))
- num_hops = len(node.solve())
- return num_hops * min_weight
- germany_map = UndirectedGraph({
- "Frankfurt": {"Mannheim": 85, "Wurzburg": 217, "Kassel": 173},
- "Mannheim": {"Karlsruhe": 80},
- "Wurzburg": {"Erfurt": 186, "Nurnberg": 103},
- "Stuttgart": {"Nurnberg": 183},
- "Kassel": {"Munchen": 502},
- "Karlsruhe": {"Augsburg": 250},
- "Nurnberg": {"Munchen": 167},
- "Augsburg": {"Munchen": 84},
- })
- def min_cena(graph):
- min_cena = infinity
- for v in graph.dict.values():
- for distance in v.values():
- if distance < min_cena:
- min_cena = distance
- return min_cena
- germany_problem = GraphProblem(Pocetok, Kraj, germany_map)
- answer = astar_search(germany_problem).path_cost
- print answer
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