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kecer

is really random?

Jan 11th, 2014
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Python 0.27 KB | None | 0 0
  1. from math import sqrt
  2. from random import randint
  3.  
  4. r = lambda:bin(randint(2**25,2**30))[2:]
  5. i = lambda x:abs(x.count("0")-x.count("1"))<=10*sqrt(len(x))
  6. ii= lambda x:abs(x.count("00")-len(x)/4)<=10*sqrt(len(x))  
  7.  
  8. for z in range(300):
  9.     x=r()
  10.     print(x)
  11.     print(i(x),ii(x))
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