nikunjsoni

99

May 11th, 2021
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C++ 1.83 KB | None | 0 0
  1. /**
  2.  * Definition for a binary tree node.
  3.  * struct TreeNode {
  4.  *     int val;
  5.  *     TreeNode *left;
  6.  *     TreeNode *right;
  7.  *     TreeNode() : val(0), left(nullptr), right(nullptr) {}
  8.  *     TreeNode(int x) : val(x), left(nullptr), right(nullptr) {}
  9.  *     TreeNode(int x, TreeNode *left, TreeNode *right) : val(x), left(left), right(right) {}
  10.  * };
  11.  */
  12. class Solution {
  13. public:
  14.     void recoverTree(TreeNode* root) {
  15.         TreeNode *first, *second, *pred, *tmp;
  16.         first = second = pred = NULL;
  17.         bool firstNode = true;
  18.        
  19.         // Morris Inorder Traversal.
  20.         TreeNode *current = root;
  21.         while(current){
  22.             if(!current->left){
  23.                 // Visit current.
  24.                 if(pred && pred->val > current->val){
  25.                     second = current;
  26.                     if(!first) first = pred;
  27.                 }
  28.                 pred = current;
  29.                 current = current->right;
  30.             }
  31.             else{
  32.                 // Find Predecessor, here tmp is predecessor.
  33.                 tmp = current->left;
  34.                 while(tmp->right && tmp->right != current)
  35.                     tmp = tmp->right;
  36.                
  37.                 // Set right of predecessor to current.
  38.                 if(!tmp->right){
  39.                     tmp->right = current;
  40.                     current = current->left;
  41.                 }
  42.                 else{
  43.                     tmp->right = NULL;
  44.                     // Visit current.
  45.                     if(pred && pred->val > current->val){
  46.                         second = current;
  47.                         if(!first) first = pred;
  48.                     }
  49.                     pred = current;
  50.                     current = current->right;
  51.                 }
  52.             }
  53.         }
  54.         swap(first->val, second->val);
  55.     }
  56. };
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