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Feb 21st, 2018
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SQL 0.43 KB | None | 0 0
  1. SELECT
  2.     *
  3. FROM
  4.     (
  5.         SELECT
  6.             companyname,
  7.             customers.customerid,
  8.             COUNT(jobnumber) AS number_of_jobs
  9.         FROM
  10.             orders
  11.         INNER JOIN
  12.             customers
  13.         ON
  14.             customers.customerid = orders.customerid
  15.         WHERE
  16.             (customers.group_company_id=1)
  17.         GROUP BY
  18.             companyname,
  19.             customers.customerid
  20.     )
  21. GROUP BY
  22.     LOWER(companyname)
  23. HAVING
  24.     COUNT(DISTINCT customers.customerid) > 1
  25. ORDER BY
  26.     companyname;
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