DiYane

equal sums even odd position 2\12

Aug 19th, 2021
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Python 0.45 KB | None | 0 0
  1. first_num = int(input())
  2. second_num = int(input())
  3.  
  4. for current_num in range(first_num, second_num + 1):
  5.     odd_digits_sum = 0
  6.     even_digit_sum = 0
  7.     current_num_str = str(current_num)
  8.     for index, digit in enumerate(current_num_str):
  9.         if index % 2 == 0:
  10.             odd_digits_sum += int(digit)
  11.         else:
  12.             even_digit_sum += int(digit)
  13.  
  14.     if odd_digits_sum == even_digit_sum:
  15.         print(current_num_str, end=' ')
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