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Apr 25th, 2017
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  1. clear;
  2. close all;
  3. skellam = Skellam(1024,0,32);
  4. k=1;
  5. Q=20;
  6. xq=linspace(-Q,Q,1024);
  7. for h=4:0.01:10
  8. j=1;
  9. for x=-20:0.6:20;
  10. suma=0;
  11. for i=1:length(skellam)
  12. if ((((skellam(i)/h)-floor(x/h))>=0) && (((skellam(i)/h)-floor(x/h))<1))
  13. suma=suma+1/h;
  14. end
  15. end
  16. wynik1(k,j)=suma/length(skellam);
  17. j=j+1;
  18. end
  19. j=1;
  20. for x=-20:0.6:20;
  21. suma=0;
  22. for i=1:length(skellam)
  23. if ((((skellam(i)/h)-(x/h))>=0) && (((skellam(i)/h)-(x/h))<1))
  24. suma=suma+1/h;
  25. end
  26. end
  27. wynik2(k,j)=suma/length(skellam);
  28. j=j+1;
  29. end
  30. suma1=0;
  31. for l=1:length(xq)
  32. suma1 = suma1+(wynik1(k,floor(xq(i)))-f(xq(i)))^2;
  33. end
  34. val1(k)=suma1/(2*Q);
  35. suma2=0;
  36. for l=1:length(xq)
  37. suma2 = suma2+(wynik2(k,floor(xq(i)))-f(xq(i)))^2;
  38. end
  39. val2(k)=suma2/(2*Q);
  40. k=k+1;
  41. end
  42. [a1 b1] = min(val1);
  43. [a1 b2] = min(val2);
  44. h=4:0.01:10;
  45. h(b2)
  46. h(b1)
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