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- // Implementation of Andrew's monotone chain 2D convex hull algorithm.
- // Asymptotic complexity: O(n log n).
- // Practical performance: 0.5-1.0 seconds for n=1000000 on a 1GHz machine.
- #include <algorithm>
- #include <vector>
- using namespace std;
- typedef double coord_t; // coordinate type
- typedef double coord2_t; // must be big enough to hold 2*max(|coordinate|)^2
- struct Point {
- coord_t x, y;
- bool operator <(const Point &p) const {
- return x < p.x || (x == p.x && y < p.y);
- }
- };
- // 3D cross product of OA and OB vectors, (i.e z-component of their "2D" cross product, but remember that it is not defined in "2D").
- // Returns a positive value, if OAB makes a counter-clockwise turn,
- // negative for clockwise turn, and zero if the points are collinear.
- coord2_t cross(const Point &O, const Point &A, const Point &B)
- {
- return (A.x - O.x) * (B.y - O.y) - (A.y - O.y) * (B.x - O.x);
- }
- // Returns a list of points on the convex hull in counter-clockwise order.
- // Note: the last point in the returned list is the same as the first one.
- vector<Point> convex_hull(vector<Point> P)
- {
- size_t n = P.size(), k = 0;
- if (n <= 3) return P;
- vector<Point> H(2*n);
- // Sort points lexicographically
- sort(P.begin(), P.end());
- // Build lower hull
- for (size_t i = 0; i < n; ++i) {
- while (k >= 2 && cross(H[k-2], H[k-1], P[i]) <= 0) k--;
- H[k++] = P[i];
- }
- // Build upper hull
- for (size_t i = n-1, t = k+1; i > 0; --i) {
- while (k >= t && cross(H[k-2], H[k-1], P[i-1]) <= 0) k--;
- H[k++] = P[i-1];
- }
- H.resize(k-1);
- return H;
- }
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