Advertisement
MatsGranvik

AX equals BY Riemann hypothesis equivalent

Dec 9th, 2020
150
0
Never
Not a member of Pastebin yet? Sign Up, it unlocks many cool features!
text 1.26 KB | None | 0 0
  1. Clear[f, A, B, n, s, a, b, x, m];
  2. f[x_] := Zeta[x];
  3. A[n_, s_] :=
  4. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[s + k/n - 1/n], {k, 1, n}]
  5. B[n_, s_] :=
  6. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[s + k/n], {k, 1, n}]
  7. X[n_, s_] :=
  8. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[-s + k/n - 1/n], {k, 1, n}]
  9. Y[n_, s_] :=
  10. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[-s + k/n], {k, 1, n}]
  11. n = 30;
  12. s = 1/3 + 14*I;
  13. s + (1/(1 - A[n, s]/B[n, s]));
  14. a = N[%, n]
  15. s = (1/3 + 14*I);
  16. -s + 1/(1 - B[n, s]/A[n, s]);
  17. b = N[%, n]
  18. s = (1/3 + 14*I);
  19. (-s + 1/(1 - X[n, s]/Y[n, s]));
  20. c = N[%, n]
  21. (a + b)
  22. (1 - (b - c))
  23. "here"
  24. (a + b)*(1 - (b - c))
  25.  
  26. Clear[A, B, a, b, s, c, X, Y, f];
  27. a = s + (1/(1 - A/B))
  28. b = -s + 1/(1 - B/A)
  29. c = (-s + 1/(1 - X/Y))
  30. Expand[(a + b)*(1 - (b - c))]
  31. Factor[%]
  32. %*(A - B)*(X - Y) - (A - B)*(X - Y)
  33. Factor[%]
  34.  
  35. f[x_] := Zeta[x];
  36. A[n_, s_] :=
  37. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[s + k/n - 1/n], {k, 1, n}]
  38. B[n_, s_] :=
  39. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[s + k/n], {k, 1, n}]
  40. X[n_, s_] :=
  41. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[-s + k/n - 1/n], {k, 1, n}]
  42. Y[n_, s_] :=
  43. Sum[(-1)^(k - 1)*Binomial[n - 1, k - 1]/f[-s + k/n], {k, 1, n}]
  44.  
  45. n = 30;
  46. s = (14 + 13/100)*I;
  47. A[n, s]*X[n, s];
  48. N[A[n, s]*X[n, s]]
  49. B[n, s]*Y[n, s];
  50. N[%, n]
Advertisement
Add Comment
Please, Sign In to add comment
Advertisement