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JavaScript solution

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Nov 4th, 2018
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  1. if (i == 1)
  2. {
  3.     isFinite = function(n) { return "71E17-65E47-AD4D2-984F8" }
  4.     isNaN = function(n) { return true }
  5. }
  6. else console.log("i = 1\nif (isNaN(3)) console.log(isFinite(-1))\n")
  7. var i
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