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a53

cifrazecmax

a53
Dec 21st, 2019
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  1. #include <fstream>
  2. using namespace std;
  3. int nr[11],p[11];
  4. int main()
  5. {
  6. int x,i=1;
  7. ifstream f("cifrazecmax.in");
  8. while(f>>x)
  9. ++nr[x/10%10],p[x/10%10]=i,++i;
  10. int Max=-1,Ind;
  11. for(int i=0;i<10;++i)
  12. if(nr[i]>Max)
  13. Max=nr[i],Ind=i;
  14. int Min=1000000000;
  15. for(int i=0;i<10;++i)
  16. if(nr[i]==Max)
  17. if(p[i]<Min)
  18. Min=p[i],Ind=i;
  19. ofstream g("cifrazecmax.out");
  20. g<<p[Ind];
  21. return 0;
  22. }
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