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Python FizzBuzz
jessicakennedy1028
Sep 9th, 2018
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Python
0.13 KB
| None
|
0
0
raw
download
clone
embed
print
report
print
(
'
\n
'
.
join
(
[
'FizzBuzz'
if
not
(
i%
3
or
i%
5
)
else
'Fizz'
if
not
i%
3
else
'Buzz'
if
not
i%
5
else
str
(
i
)
for
i
in
range
(
1
,
100
)
]
)
)
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