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- # Chapter 11 problems 5 & 6
- ## ch 11 prob 5
- > data=read.csv("C:/Users/benny/Downloads/ch11_prob5_data.csv")
- > View(data) #this data looks stacked already
- # in tutorial: 'values' = biomass & 'group' = species, 'dataset' = data
- > data$species=as.factor(data$species) #makes sure the factors are read as distinct factors
- # for each group n=10, which is small, so we check ANOVA for Normality
- > shapiro.test(residuals(lm(biomass~species,data))) #IDK WHAT I DID DIFFERENT FROM LAST NIGHT BUT IT WORKS NOW. CODING IS SO
- # FRUSTRATING ##i checked, i swapped biomass and species
- # W = 0.96669 pval = 0.2814, not (lessthan/equalto)0.05, therefore pop dist is Normal
- > bartlett.test(biomass~species,data)
- #k-sq'd=0.72394 df=3 p-val=0.8676 (>0.05 therefore "insufficient evidence to suggest that the group variances differ", therefore
- # equal var. ANOVA is appropriate)
- > summary(aov(biomass~species,data)) #one-way ANOVA test w equal variances
- # Pr(>F)= 0.00287
- > TukeyHSD(aov(biomass~species,data))
- ######################################
- ## problem 6 - environmental lead ##
- ######################################
- > data=read.csv("C:/Users/benny/Downloads/ch11_prob6_data.csv")
- > View(data)
- # 'group' = year, 'values' = lead #
- > data$year=as.factor(data$year)
- > shapiro.test(residuals(lm(lead~year,data)))
- # w=0.86602 p-value=1.197e-13 (super small)
- > library(psych)
- > describeBy(data$lead,data$year)
- > summary(aov(lead~year,data))
- #p-val=0.0673
- > TukeyHSD(aov(lead~year,data))
- ###^^^^^^^^^^^^^^^^^^^^###
- ## prob 7 - cont. off 6 ##
- > boxplot(lead~year,data)
- > kruskal.test(lead~year,data)
- > install.packages("DescTools")
- > library(DescTools)
- > NemenyiTest(x=data$lead,g=data$year,dist = "tukey") #sample sizes (n) are equal, so we use Nemenyi test
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