Beer Time with Reg Ex

import java.util.Scanner;
import java.util.regex.Matcher;
import java.util.regex.Pattern;

public class BeerTime {
    public static void main(String[] args) {
        Scanner myScan = new Scanner(System.in);
        String time = myScan.nextLine();
        Pattern pattern = Pattern.compile("^(?<Hour>[01]?\\d):(?<Min>\\d{2}) (?<AmPm>[AP]M)$");
        Matcher matcher = pattern.matcher(time);
        String result = "";
        if (!matcher.find()) {
            result = "invalid time";
        } else {
            int hour = Integer.parseInt(matcher.group("Hour"));
            int minutes = Integer.parseInt(matcher.group("Min"));
            String am_pm = matcher.group("AmPm");
            if (hour < 1 || hour > 12 || minutes < 0 || minutes > 59) {
                result = "invalid time";
            } else if (hour > 0 && hour < 12 && am_pm.equals("PM") ||
                      (hour == 12 || hour > 0 && hour < 3) && am_pm.equals("AM")) {
                result = "beer time";
            } else {
                result = "non-beer time";
            }
        }
        System.out.println(result);
    }
}