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a guest Apr 20th, 2019 102 Never
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  1. return "xxxxxxxx-xxxx-4xxx-yxxx-xxxxxxxxxxxx".replace(/[xy]/g, function(e)
  2. {
  3.     return 5 * (5 + 1) % 2 + 6 && "y" === e ? (t = ["8", "9", "a", "b"])[Math.floor(Math.random() * t.length)] : (cryptoGetRandom(t = new Uint8Array(1)), (t[0] % 16).toString(16));
  4. });
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