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Jan 30th, 2022
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  1. for (j = 0; j < n - 1; j++) { ////////////////////////////first step
  2. for (i = n - 1; i > j; i--) {
  3. f[i] = (f[i] - f[i - 1]) / (x[i] - x[i - j - 1]);
  4. }
  5. }
  6. for (i = n - 1; i >= 0; i--) { ////////////////////////////second step
  7. mult = 1;
  8. for (j = 0; j < i; j++)
  9. mult *= (test - x[j]);
  10. mult *= f[j];
  11. sum += mult;
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