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a guest Jan 18th, 2019 61 Never
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  1. <?php
  2.  
  3. if (!$res = mysql_query($sql, $con)) {
  4.     die("SQL Error: " . mysql_error());
  5. } else {
  6.     echo "Successfully updated " . mysql_affected_rows($res) . " rows of data.");
  7. }
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