Project Euler#17 Number letter counts

#If the numbers 1 to 5 are written out in words: one, two, three, four, five, then there are 3 + 3 + 5 + 4 + 4 = 19 #letters used in total.

#If all the numbers from 1 to 1000 (one thousand) inclusive were written out in words, how many letters would be #used?

#NOTE: Do not count spaces or hyphens. For example, 342 (three hundred and forty-two) contains 23 letters and 115 #(one hundred and fifteen) contains 20 letters. The use of "and" when writing out numbers is in compliance with #British usage.



numbers = {0:'',1:'one',2:'two',3:'three',4:'four',5:'five',6:'six',7:'seven'
           ,8:'eight',9:'nine',10:'ten',11:'eleven',12:'twelve',13:'thirteen'
           ,14:'fourteen',15:'fifteen',16:'sixteen',17:'seventeen',18:'eighteen'
           ,19:'nineteen',20:'twenty',30:'thirty',40:'forty',50:'fifty'
           ,60:'sixty',70:'seventy',80:'eighty',90:'ninety'}

lettersCount = 0

for i in range(1,1001):

    if i < 20:
        lettersCount += len(numbers[i])


    elif i >= 20 and i < 100:
        lettersCount += len(numbers[(i/10)*10]) + len(numbers[i%10])


    elif i >= 100 and i < 1000:

        if i%100 == 0:
            lettersCount += len(numbers[(i/100)]) + len('hundred')

        elif i%100 > 10 and i%100 < 20:
            lettersCount += len(numbers[(i/100)]) + len('hundredand')\
            + len(numbers[i%100])
        else:
            lettersCount += len(numbers[(i/100)]) + len('hundredand')\
            + len(numbers[((i%100)/10)*10]) + len(numbers[(i%100)%10])

    elif i == 1000:
        lettersCount += len('onethousand')

print lettersCount