yes

#include <algorithm>
#include <iostream>
#include <iomanip>
#include <numeric>
#include <vector>
using namespace std;

int main()
{
    int t = 0, n = 0, sum, cnt;
    double temp = 0, ans, cmax;
    cin >> t;
    for (size_t i = 0; i < t; i++)
    {
        ans = 0;
        cmax = INT_MIN;
        cnt = 0;
        sum = 0;
        cin >> n;
        for (size_t j = 0; j < n; j++)
        {
            cin >> temp;
            sum += temp;
            if (temp > cmax) cmax = temp;
        }
        ans = cmax + (double)((sum - cmax) / (n - 1));
        cout << fixed << setprecision(9) << ans << endl;
    }
}