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Apr 23rd, 2017
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  1. def is_balanced(str):
  2. Stack stack
  3. for char in str:
  4. if char in [ '(', '[' ]:
  5. stack.push(char)
  6. else:
  7. if stack.empty(): return False
  8. top <- stack.pop()
  9. if (top = '[' and char != ']') or
  10. (top = '(' and char != ')'):
  11. return False
  12. return stack.empty()
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