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STANAANDREY

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May 7th, 2023
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  1. segments[0] = {1, 1, 1, 50000};
  2. segments[n - 1] = {50000, 1, 50000, 50000};
  3. for (int i = 2; i < n - 1; ++i) {
  4. //cin >> segments[i].x1 >> segments[i].y1 >> segments[i].x2 >> segments[i].y2;
  5. segments[i] = {i % 2, i, 50000, i};
  6. }
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