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smmac72
Mar 30th, 2023
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Python
0.16 KB
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def
spell_difficulty
(
spells
)
:
counter
=
0
for
i
in
spells:
if
len
(
i
)
>
8
or
len
(
i.
split
(
)
)
>=
2
:
counter +
=
1
return
counter
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