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Write a program to sum all adjacent equal numbers in a list of decimal numbers, starting from left to right.
 After two numbers are summed, the obtained result could be equal to some of its neighbors and should be summed as well (see the examples below).
 Always sum the leftmost two equal neighbors (if several couples of equal neighbors are available).

Input   Output  Explanation
3 3 6 1 12 1    3 3 6 1  6 6 1  12 1
8 2 2 4 8 16    16 8 16 8 2 2 4 8 16  8 4 4 8 16  8 8 8 16  16 8 16
5 4 2 1 1 4 5 8 4   5 4 2 1 1 4  5 4 2 2 4  5 4 4 4  5 8 4
0.1 0.1 5 -5    0.2 5 -5    0.1 0.1 5 -5  0.2 5 -5




package TechModule;

import java.math.BigDecimal;
import java.text.DecimalFormat;
import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Scanner;
import java.util.stream.Collector;
import java.util.stream.Collectors;

public class p04_ListsSumAdjacentEqualNumbers {
    public static void main(String[] args){
            Scanner scanner = new Scanner(System.in);
            //double[] readingNumbers=(Arrays.stream(scanner.nextLine().split(" ")).mapToDouble(Double::parseDouble).toArray());

                    List<Double>numbers = Arrays.stream(scanner.nextLine().split(" ")).map(Double::parseDouble).collect(Collectors.toList());



         for (int i=0;i<numbers.size();i++){
             for (int j = 0; j <i ; j++) {
                 double a = numbers.get(j);
                 double b= numbers.get(j+1);
                 if (numbers.get(j).equals(numbers.get(j+1))) { // ако го сравнявам с numbers.get(j)==(numbers.get(j+1)), го  пропуска , направих си първо две променливи а и б и така го прилъгах… после го направих с equals и проработи 😉
                  double result=numbers.get(j)+numbers.get(j+1);
                     numbers.set(j,result ) ;
                     numbers.remove(numbers.get(j + 1));
                     i=0;

                 }
             }

         }
        for (double number: numbers)
              {
                  System.out.print(new DecimalFormat("#.### ").format(number));

        }

           }
}