View difference between Paste ID: qqQixPw7 and rCmvJC3T

 The Input of http://pastebin.com/F9ZDQZYC is: "THE EYES ARE USELESS WHEN THE MIND IS BLIND".
 
 
-I've studied Code #2 a little bit more after I made it and discovered a few things about it that will hopefully make it easier for you to understand.
+Code #3 is like Code #1 but you're now able to use multiple instances of the same letter and its output varies.
 
 Our input will be: "HELLO WORLD" and we'll encode one word at a time.
-Code #2 & 3 are a lot less picky than Code #1.
+
-To understand Code #2, it'd be best if you already understood how the Vigenere Cipher works.
+HELLO is 5 characters long, meaning we need to make a 5x5 square & fill in the alphabet.
 
 	1	2	3	4	5
-There are 5 different groups of letters:
+1	A	B	C	D	E
 2	F	G	H	I	J
-1: UCSD
+3	K	L	M	N	O
-2: QBVGLP
+4	P	Q	R	S	T
-3: YJNRZT
+5	U	V	W	X	Y
-4: AMFKWX
+
-5: EIHO
+Since we've filled the whole 5x5 square with most of the alphabet(A-Y), the "Z" will be apart of the next group(A) of 5x5 squares.
 
-The reason why I chose for the letters to be in those specific groups/order is irrelevant now, so all you need to make note of is that for this code, the letters are in that arrangment.
+------------1st GROUP has no Group letter------------
 	1	2	3	4	5
-Now we just create a vigenere table with these letters:
+1	A	B	C	D	E
 2	F	G	H	I	J
-The first column will just be the regular alphabet in order, (A-Z), and the 2nd column will be next instance of that particular row/group.
+3	K	L	M	N	O
 4	P	Q	R	S	T
-For example:
+5	U	V	W	X	Y
 ------------2nd Group will be defined by "A"------------
-1st column up to 5 letters:
+	1	2	3	4	5
-1
+1	Z	_	_	_	_
-A
+2	_	_	_	_	_
-B
+3	_	_	_	_	_
-C
+4	_	_	_	_	_
-D
+5	_	_	_	_	_
-E
+
 
-1st & 2nd column up to 5 letters:
+Our output will now have a padding of "X"'s, and it will be as long as how many spots are in the group (in this case, 5x5=25)
 
-1	2
+XXXXXXXXXXXXXXXXXXXXXXXXX
-A	M
+
-B	V
+
-C	S
+Just like Code #1, Knowing the number form of letters, A=1,B=2,C=3...Z=26, We now place the order letter in the position of the letter's number.
-D	U
+
-E	I
+(H)ELLO		XXXXXXX1XXXXXXXXXXXXXXXXX
 
-Because:
+If our first letter happened to be "Z", then we would know that "Z" is apart of GROUP A, BUT is in the 1st postion in the 5x5 grid, meaning:
 
-Row A is apart of this group: AMFKWX
+Our Z, (1st character being encoded: Order number = 1), would be in the 1st postion of our output:
-ROW B is apart of this group: QBVGLP
+
-ROW C is apart of this group: UCSD
+(Z)ello		(X)XXXXXXXXXXXXXXXXXXXXXXXX
-ROW D is apart of this group: UCSD
+
-ROW E is apart of this group: EIHO
+(Z)ello		(1)XXXXXXXXXXXXXXXXXXXXXXXX
 
-Meaning:
+Since "Z" is in Group A, we need to show that in your output by adding ".A" after the "1":
 
-Columns & Rows 1-5 would be:
+(Z)ello		(1.A)XXXXXXXXXXXXXXXXXXXXXXXX
-1	2	3	4	5
+
-A	M	F	K	W
+and it would look like this:
-B	V	G	L	P
+
-C	S	D	U	C
+(Z)ello		1.AXXXXXXXXXXXXXXXXXXXXXXXX
-D	U	S	D	U
+
-E	I	H	O	E
+
 Now back to our actual input: H(E)LLO
 
-You would do this for the 26 columns and 26 rows thus making a vigenere table using these letter configurations.
+H(E)LLO		XXXX2XX1XXXXXXXXXXXXXXXXX
 
 HE(L)LO		XXXX2XX1XXX3XXXXXXXXXXXXX
-So if we have an input of: TEST CODE
+
 
-We encode by finding (T)EST on the top row of the vigenere table and the T(E)ST on the Left most column and find the intersection between the two, which would be: O
+Now we have a 2nd instance of the same letter (two L's), All we do to show that multple letters are apart of that position is add a "|" between them:
 
-Continue to do this process until the last letter of the word:
+HEL(L)O		XXXX2XX1XXX3|4XXXXXXXXXXXXX
 
-TEST = OST
+HELL(O)		XXXX2XX1XXX3|4XX5XXXXXXXXXX
 
-For the last letter, you find TES(T) on the top row and (T)EST on the left most column, which would be: Y
+
 and if we had to encode a letter from a different group, same rules apply.
-Now continue this process for the rest of the input, TEST CODE, and it will leave you an output of: OSTY ICOC
+
 If you find it a bit hard to understand when trying to decode, space out the columns:
 
 Final:
 HELLO = XXXX2XX1XXX3|4XX5XXXXXXXXXX
 
 Final with 25 columns spaced out:
 HELLO = X	X	X	X	2	X	X	1	X	X	X	3|4	X	X	5	X	X	X	X	X	X	X	X	X	X
 
 
 To save time, Here is how the rest of the input would look:
 
 
 HELLO WORLD:
 
 XXXX2XX1XXX3|4XX5XXXXXXXXXX
 XXX5XXXXXXX4XX2XX3XXXX1XXX
 
 
 Essentially, you can also do the same thing as Code #1 and repeat the numbers if you wanted to:
 
 HELLO WORLD:
 
 222221113333|45552222222222
 55554444444422233311111555
 
 
 That's all there is to this code. :D
 
 Thanks for participating for Code #1! :D
 
 
  - DWC