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| 1 | - | salut, ma confrunt cu o situatie ciudata. Aceste FIND and REPLACE nu merg. Adica find merge, dar replace nu merge. |
| 1 | + | Hi, I'm facing a strange situation. These FIND and REPLACE do not work. That is, finding works, but replacing does not work. |
| 2 | ||
| 3 | - | In aceste 3 situatii, trebuie sa inlocuiesc un anuit regex cu (spatiu gol). Vezi acolo acel ' ' |
| 3 | + | In these 3 situations, I have to replace an annuit regex with (empty space). See that '' there |
| 4 | - | Daca la re.findall as pune orice regex simplu, de exemplu un html tag <div> atunci se face inlocuirea perfect. |
| 4 | + | If at re.findall I put any simple regex, for example an html tag <div> then the replacement is done perfectly. |
| 5 | - | Dar daca este un alt gen de regex, cum sunt cele de mai jos, inlocuirea nu se mai face. Adica nu se intampla nimic... |
| 5 | + | But if it is a different kind of regex, such as the ones below, the replacement is no longer done. I mean nothing happens ... |
| 6 | ||
| 7 | ||
| 8 | if len(re.findall('(?!<p>).+?(?<!</p>)$', page_text)) != 0:
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| 9 | page_text = re.sub('(?!<p>).+?(?<!</p>)$', '', page_text)
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| 10 | counter_img += 1 | |
| 11 | OR | |
| 12 | ||
| 13 | if len(re.findall('^\s+</p>', page_text)) != 0:
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| 14 | page_text = re.compile(r'', page_text) | |
| 15 | counter_img += 1 | |
| 16 | ||
| 17 | OR | |
| 18 | ||
| 19 | if len(re.findall('\n\s*', page_text)) != 0:
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| 20 | page_text = re.sub('\n\s*', '', page_text)
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| 21 | counter_img += 1 | |
| 22 |
