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| 1 | - | RG Code: |
| 1 | + | Code: |
| 2 | - | 00000001 |
| 2 | + | #include<iostream> |
| 3 | - | 00000002 |
| 3 | + | #include<stdio.h> |
| 4 | - | 00000003 |
| 4 | + | using namespace std; |
| 5 | - | 00000004 |
| 5 | + | int power(int n, int i) |
| 6 | - | 00000005 |
| 6 | + | {
|
| 7 | - | 00000011 |
| 7 | + | if(i==0) return 1; |
| 8 | - | 00000022 |
| 8 | + | else return n*power(n,i-1); |
| 9 | - | 00000033 |
| 9 | + | } |
| 10 | - | 00000044 |
| 10 | + | |
| 11 | - | 00000055 |
| 11 | + | void assigndectohex(int*a, int n) |
| 12 | - | 00000101 |
| 12 | + | {
|
| 13 | - | 00000202 |
| 13 | + | for(int i=7;i>=0;i--) |
| 14 | - | 00000303 |
| 14 | + | {
|
| 15 | - | 00000404 |
| 15 | + | a[i]=n%6; |
| 16 | - | 00000505 |
| 16 | + | n=n/6; |
| 17 | - | 00001111 |
| 17 | + | } |
| 18 | - | 00002222 |
| 18 | + | } |
| 19 | - | 00003333 |
| 19 | + | |
| 20 | - | 00004444 |
| 20 | + | int hextodec(int*a) |
| 21 | - | 00005555 |
| 21 | + | {
|
| 22 | - | 00010001 |
| 22 | + | int n=0; |
| 23 | - | 00020002 |
| 23 | + | for(int i=0;i<8;i++) |
| 24 | - | 00030003 |
| 24 | + | n=n+a[i]*power(6,i); |
| 25 | - | 00040004 |
| 25 | + | return n; |
| 26 | - | 00050005 |
| 26 | + | } |
| 27 | - | 00110011 |
| 27 | + | |
| 28 | - | 00220022 |
| 28 | + | int main() |
| 29 | - | 00330033 |
| 29 | + | {
|
| 30 | - | 00440044 |
| 30 | + | FILE*fp=fopen("omo39out.txt","w");
|
| 31 | - | 00550055 |
| 31 | + | int a[8][8], flag,count; |
| 32 | - | 01010101 |
| 32 | + | for(int n=1;n<=1679615;n++) |
| 33 | - | 02020202 |
| 33 | + | {
|
| 34 | - | 03030303 |
| 34 | + | flag=1; |
| 35 | - | 04040404 |
| 35 | + | assigndectohex(a[0],n); |
| 36 | - | 05050505 |
| 36 | + | for(int i=1;i<8;i++) |
| 37 | {
| |
| 38 | for(int j=0;j<8;j++) | |
| 39 | {
| |
| 40 | a[i][(j+7)%8]=a[i-1][j]; | |
| 41 | - | 55555555 |
| 41 | + | } |
| 42 | - | 40 |
| 42 | + | } |
| 43 | ||
| 44 | - | SM Code: |
| 44 | + | for(int i=1;i<8;i++) |
| 45 | {
| |
| 46 | if((hextodec(a[i])%hextodec(a[0]))!=0) | |
| 47 | {
| |
| 48 | flag=0; break; | |
| 49 | } | |
| 50 | } | |
| 51 | ||
| 52 | if(flag==1) | |
| 53 | {
| |
| 54 | count++; | |
| 55 | for(int i=0;i<8;i++) | |
| 56 | {fprintf(fp,"%d", a[0][i]);}
| |
| 57 | fprintf(fp,"\n"); | |
| 58 | } | |
| 59 | } | |
| 60 | fclose(fp); | |
| 61 | printf("So count of such numbers=%d",count);
| |
| 62 | return 0; | |
| 63 | } | |
| 64 | //Output: | |
| 65 | 10000000 | |
| 66 | 10001000 | |
| 67 | 10100000 | |
| 68 | 10101010 | |
| 69 | 11000000 | |
| 70 | 11001100 | |
| 71 | 11110000 | |
| 72 | 11111111 | |
| 73 | 20000000 | |
| 74 | 20002000 | |
| 75 | 20200000 | |
| 76 | 20202020 | |
| 77 | 22000000 | |
| 78 | 22002200 | |
| 79 | 22220000 | |
| 80 | 22222222 | |
| 81 | 30000000 | |
| 82 | 30003000 | |
| 83 | 30300000 | |
| 84 | 30303030 | |
| 85 | 33000000 | |
| 86 | 33003300 | |
| 87 | 33330000 | |
| 88 | 33333333 | |
| 89 | 40000000 | |
| 90 | 40004000 | |
| 91 | 40400000 | |
| 92 | 40404040 | |
| 93 | 44000000 | |
| 94 | 44004400 | |
| 95 | 44440000 | |
| 96 | 44444444 | |
| 97 | 50000000 | |
| 98 | 50005000 | |
| 99 | 50500000 | |
| 100 | 50505050 | |
| 101 | 55000000 | |
| 102 | 55005500 | |
| 103 | 55550000 | |
| 104 | 46 |