View difference between Paste ID: DwyL1ygv and cDUpCwEx

 #include <stdio.h>
 #include <stdlib.h>
 
 int leap(int x){
     if(x%4 == 0 && x%100 != 0 || x%400 == 0)
         return 1;
     else
         return 0;
 }
 
 int pastDays(int m, int d, int y){
-    int days[] = {31,28,31,30,31,30,31,30,31,30,31};
+
     int i, past = 0;
 
     if(leap(y)){
         days[1] = 29;
     }
 
     for(i = 0; i < m-1; i++){
         past = past + days[i];
     }
     return past + d;
 }
 
 int daysPast(int d, int y) {
     int days[] = {31,28,31,30,31,30,31,31,30,31,30,31};
 
     int i, temp = 0;
 
     if(leap(y)){
         days[1] = 29;
     }
 
     for(i = 0; i < 11 && d > days[i]; i++){
         d = d - days[i];
     }
 
     if(d < 0){
         d = days [i] + d;
     }
     printf("\n\t\t%d/%d/%d", i+1,d, y);
 
 }
 
 int main()
 {
     int choice, past, mm, dd, yy, temp;
     char more;
     printf("\n\t\tThis program will find days past or date in the year");
 
     do{
         printf("\n\t\t1)  date      -> days past");
         printf("\n\t\t2)  days past -> date");
         printf("\n\t\tYour choice (1/2)?");
         scanf("%d", &choice);
         if(choice == 1){
             printf("\n\t\tInput date (mm/dd/yyyy)");
             scanf("%d/%d/%d", &mm, &dd, &yy);
             if(mm > 12) {
                 printf("\n\t\tThere are not more than 13 months in a year");
             }
             else if(dd > 31){
                 printf("\n\t\tCant have more than 31 days in a month");
             }
             else if(mm == 2 && dd > 28 && leap(yy) != 1 || mm == 2 && dd > 29 && leap(yy) == 0){
                 printf("\n\t\tThere are not more than 28 day in February %d", yy);
             }
             else{
                 printf("\n\t\tThere are %d days past in the year", pastDays(mm, dd, yy));
             }
         }
         else if(choice == 2) {
             printf("\n\t\tInput days past (ddd)");
             scanf("%d", &past);
             printf("\n\t\tInput the year (yyyy)");
             scanf("%d", &yy);
             if(past == 366 && leap(yy) == 0){
                 printf("\n\t\tError there's not 366 days in %d", yy);
             }
             else if(past > 365) {
                 yy = yy + 1;
                 past = past - 365;
                 daysPast(past, yy);
             }
             else if(past < 0){
                 yy = yy -1;
                 past = 365 + past;
                 daysPast(past, yy);
             }
             else{
                 daysPast(past, yy);
             }
         }
 
         printf("\n\t\tDo more (Y/N)");
         scanf("%s", &more);
     }while(more == 'y' || more == 'Y');
 
 
     return 0;
 }