def InversePrandtlMeyer(nu):
    nu=nu*3.14/180
    A=1.3604
    B=0.0962
    C=-0.5127
    D=-0.6722
    E=-0.3278
    nu_0=0.5*3.14*(2.5-1)
    y=(nu/nu_0)**(2/3)
    Mach=(1 + A*y + B*y**2 + C*y**3)/(1 + D*y + E*y**2)
    return Mach = InversePrandtlMeyer(nu)
print(InversePrandtlMeyer(2))