How do I programmatically return the max of two integers without

a -= b;
a &= (~a) >> 31;
a += b;

a -= b;
a &= a >> 31;
a += b;

r = x - ((x - y) & -(x < y)); // max(x, y)

int data[2] = {a,b};
int c = a - b;
return data[(int)((c & 0x80000000) >> 31)];

int max(int a, int b)
{
        int x = (a - b) >> 31;
        int y = ~x;
        return (y & a) | (x & b);
}

int getMax(int a, int b)
{
    for(int i=0; (i<a) || (i<b); i++) { }
    return i;
}

let greater x y = signum (1+signum (x-y))

let max a b = (greater a b)*a + (greater b a)*b

// GCC inline assembly
int max(int a, int b)
{
  __asm__("movl %0, %%eaxnt"   // %eax = a
          "cmpl %%eax, %1nt"   // compare a to b
          "cmovg %1, %%eax"      // %eax = b if b>a
         :: "r"(a), "r"(b));
}

int max(int a, int b)
{
  __asm__("movl %0, %%eaxnt"
      "subl %1, %%eaxnt"
          "cmovge %0, %%eaxnt"
          "cmovl %1, %%eax"
         :: "r"(a), "r"(b)
         :"%eax");
}

#define H0(x)       (((signed)(x)) >> (sizeof((signed)(x))*8-1))
#define H1(a,b)     H0((a)-(b))

#define MIN1(a,b)   ((a)+(H1(b,a) & ((b)-(a))))
#define MIN2(a,b)   ((a)-(H1(b,a) & ((a)-(b))))
#define MIN3(a,b)   ((b)-(H1(a,b) & ((b)-(a))))
#define MIN4(a,b)   ((b)+(H1(a,b) & ((a)-(b))))
//#define MIN5(a,b)   ((a)<(b)?(a):(b))
//#define MIN6(a,b)   ((a)>(b)?(b):(a))
//#define MIN7(a,b)   ((b)>(a)?(a):(b))
//#define MIN8(a,b)   ((b)<(a)?(b):(a))

#define MAX1(a,b)   ((a)+(H1(a,b) & ((b)-(a))))
#define MAX2(a,b)   ((a)-(H1(a,b) & ((a)-(b))))
#define MAX3(a,b)   ((b)-(H1(b,a) & ((b)-(a))))
#define MAX4(a,b)   ((b)+(H1(b,a) & ((a)-(b))))
//#define MAX5(a,b)   ((a)<(b)?(b):(a))
//#define MAX6(a,b)   ((a)>(b)?(a):(b))
//#define MAX7(a,b)   ((b)>(a)?(b):(a))
//#define MAX8(a,b)   ((b)<(a)?(a):(b))

#define ABS1(a)     (((a)^H0(a))-H0(a))
//#define ABS2(a)     ((a)>0?(a):-(a))
//#define ABS3(a)     ((a)>=0?(a):-(a))
//#define ABS4(a)     ((a)<0?-(a):(a))
//#define ABS5(a)     ((a)<=0?-(a):(a))