XSLT dividing a list of nodes in half

<xsl:for-each select="./node [position() <= (count(*) div 2)]">
    <li>foo</li>
</xsl:for-each>
<xsl:for-each select="./node [count(*) div 2 < position()]">
    <li>bar</li>
</xsl:for-each>

<xsl:variable name="nodes" select="node"/>
<xsl:variable name="mid" select="count($nodes) div 2"/>
<xsl:for-each select="$nodes[position() <= $mid]">
  <li>foo</li>
</xsl:for-each>
<xsl:for-each select="$nodes[$mid < position()]">
  <li>bar</li>
</xsl:for-each>

<xsl:for-each select="./node [position() <= last() div 2]">
   <li>foo</li>
</xsl:for-each>
<xsl:for-each select="./node [last() div 2 < position()]">
   <li>bar</li>
</xsl:for-each>

<xsl:for-each select="node[position() <= (count(../node) div 2)]">
    ...
</xsl:for-each>
<xsl:for-each select="node[(count(../node) div 2) < position()]">
    ...
</xsl:for-each>