Unique FizzBuzz Solution

# Magnie Mozios' Fizz Buzz program.
# MagnieTheReal[at]gmail.com -- Copyright 2014 -- All Mine, except line 25.
# Version 1.0 original, working, program.
# Version 1.1 for cleaner output.
__version__ = '1.1'

# Declare the characters.
f = ord('f')
i = ord('i')
z = ord('z')
b = ord('b')
u = ord('u')

# Make writing 'zz' easier.
zz = chr(z) * 2

# Add all the characters together to make a string.
fizz = chr(f) + chr(i) + zz
buzz = chr(b) + chr(u) + zz

# Declare the numbers, import math for necessary functions used in declarations.
import math
three = int((math.pi * 13.37)) / 14.0
# Thanks to hobbes[at]fallingduck.net for this.
five = float(int((math.acos(math.e - 2) * (math.pi ** 2)) - 2))

# Go through 1 to 100
for i in xrange(1, 100):
    # Print the result
    print ''.join((  # Use tuple so input is one argument.
        str(i) + ' ',  # Print the current number
        (fizz) if not (i % three) else '',  # Print 'fizz' if divisible by 3.
        (buzz) if not (i % five) else ''  # Print 'buzz' if divisible by 5.
    ))