Factors of a Number

from math import sqrt


def factors(num):
    count = 0
    ite = int(sqrt(num))
    i = 1
    while(i <= ite):
        if num % i == 0:
            count += 1
        i += 1
    count = 2 * count
    if ite * ite == num:
        count -= 1
    return count

test_case = int(input("Enter a number to find no of factors: "))
print('Factors count: ', factors(test_case))